Kamis, 15 November 2007

Soal Remedial Pewarisan Sifat

ULANGAN HARIAN
Mata Pelajaran : IPA
Kelas : IX
Kompetensi Dasar : 2.3


Pilihlah salah satu huruf a, b, c atau d sebagai jawaban yang anda anggap paling benar dan tepat


1. Gen adalah …
a. unit terkecil dari kromosom yang mengandung satuan sifat keturunan yang akan diwariskan
b. unit teresar dari kromosom yang membawa sifat-sifat keturunan
c. kromosom yang mengalami perubahan dalam proses pembelahan sel
d. satuan terbesar dari sel
2. Jika di dalam sel tubuh jagung mengandung 20 kromosom, maka jumlah diploidnya adalah …
a. 10 kromosom c. 30 kromosom
b. 20 kromosom d. 40 kromosom
3. Dalam suatu perkawinan kedua gen memiliki sifat yang sama-sama kuat disebut …
a. Dominan c. resesif
b. dominant penuh d. intermediat
4. Dalam persilangan monohibrida dengan sifat intermediat, rasio fenotif pada F2 adalah …
a. 1:3 c. 1:2:1
b. 3:1 d. 4:1
5. Pada persilangan monohibrida dominan penuh, individu F2 menghasilkan rasio fenotif …
a. 1:3 c. 1:2:1
b. 3:1 d. 4:1
6. Bunga mawar merah dominan ( Bb ) disilangkan dengan bunga mawar putih ( bb ), dari persilangan itu dihasilkan F1 ….
a. Merah c. merah muda
b. Putih d. merah putih
7. Individu yang memiliki genotif homozigot resesif disimbolkan dengan huruf …
a. AA c. a∆
b. Aa d. aa
8. Bila dalam suatu persilangan dihasilkan perbandingan keturunan 2:2 maka kemungkinan genotif induknya adalah …
a. AA x aa c. aa x aa
b. Aa x Aa d. Aa x aa
9. Ibu mata normal badan tinggi dominan dengan genotif TTYY dengan laki-laki pendek mata sipit , maka F1 bergenotif TtYy dan berfenotif …
a. badan tinggi mata normal
b. badan tinggi mata sipit
c. badan pendek mata sipit
d. badan pendek mata normal
10. Gamet yang dapat dibentuk oleh individu TtGg adalah …
a. TT, tt , GG dang g
b. TG, Tg, tG dan tg
c. TT, TG, Tg dan tg
d. Tg, Tg, TG dan tg
11. Penyakit kerurunan yang terpaut kromosom sex adalah …
a. cacat mental dan buta warna
b. cacat mental dan hemofilia
c. buta warna dengan hemofilia
d. hemofilia dengan deman berdarah
12. Jumlah individu F2 dari persilangan dengan 3 sifat beda akan menghasilkan individu sebanyak …
a. 3 buah c. 64 buah
b. 18 buah d. 256 buah
13. Bila perempuan hemofilia kawin dengan laki-laki normal maka …
a. semua anak laki-lakinya hemofilia
b. semua anak perempuannya hemofilia
c. semua anak perempuannya normal
d. semua anak laki-lakinya normal
14. Eko bermata normal menikah dengan Rini yang bersifat carier buta warna, kemungkinan fenotife anak-anaknya adalah …
a. perempuan normal 75%, perempuan carier 25%
b. laki-laki butawara 75%, perempuan carier 25%
c. laki-laki buta warna 25%, perempuan normal 50%
d. perempuan normal 25%, perempuan carier 25%
15. Yang bukan alasan Mendel menggunakan kacang ercis dalam penelitiannya adalah …
a. memiliki pasangan sifat yang mencolo
b. dapat melakukan penyerbukan sendiri
c. umur keturunannya pendek
d. tidak dapat melakukan penyerbukan silang




Jawablah dengan rinci
Buatlah tabel persilangan intermediat antara ubi Cilembu merah dengan ubi Cilembu putih
a. tentukan gamet F1 dan F2
b. tentukan fenotif dan genotif F1
c. tentukan fenotif dan genotif F2
d. Tentukan rasio fenotif dan genotif F2

36 komentar:

ALLES mengatakan...

Nama : ALLES TIO JORDAN
Kelas : IX.4

1. A
2. B
3. D
4. C
5. B
6. C
7. D
8. B
9. B
10. B

Jawaban essay

F1 = P = Ubi cilembu merah x Ubi cilembu putih
F = merah x putih
G = MM x mm
M x m
M x m






Genotif F2 = P = Ubi cilembu merah muda x Ubi cilembu merah muda
(Mm) x (Mm)
F = pink x pink
G= Mm x Mm

Genotif F2= MM : Mm : mm
1 : 2 : 1 = 25% : 50% : 25%

Fenotif F2= merah ; merah muda ; putih
1 : 2 : 1 = 25% ; 50% ; 25%

Jadi , a) Gamet F1 & F2= Mm x mm : Mm x Mm
b) Fenotif F1 = 100% pink Genotif F1 = 100% Mm
c) Fenotif F2 = merah , pink , putih : Genotif F2= Mm , Mm , mm
d) Rasio fenotif = 1 : 2 : 1 Rasio Genotif = 1 : 2 : 1
25% : 50% : 25% 25% ; 50% : 25%

missNEILpotter mengatakan...

Nama : NEILDEVA DESPENDYA PUTRI
Kelas : IX.2

1. A
2. B
3. D
4. C
5. B
6. C
7. D
8. B
9. B
10. B

Jawaban essay

F1 = P = Ubi cilembu merah x Ubi cilembu putih
F = merah x putih
G = MM x mm
M x m
M x m






Genotif F2 = P = Ubi cilembu merah muda x Ubi cilembu merah muda
(Mm) x (Mm)
F = pink x pink
G= Mm x Mm

Genotif F2= MM : Mm : mm
1 : 2 : 1 = 25% : 50% : 25%

Fenotif F2= merah ; merah muda ; putih
1 : 2 : 1 = 25% ; 50% ; 25%

Jadi , a) Gamet F1 & F2= Mm x mm : Mm x Mm
b) Fenotif F1 = 100% pink Genotif F1 = 100% Mm
c) Fenotif F2 = merah , pink , putih : Genotif F2= Mm , Mm , mm
d) Rasio fenotif = 1 : 2 : 1 Rasio Genotif = 1 : 2 : 1
25% : 50% : 25% 25% ; 50% : 25%

LEVANI mengatakan...

NAMA : LEVANI DESTIARA
KELAS:IX-3

1.B
2.D
3.D
4.C
5.B
6.C
7.D
8.D
9.A
10.B
11.C
12.C
13.D
14.B
15.D

Jawaban Esay

A}Gamet F1:M DaN m
Gamet F2:MM,Mm,mM,mm

B}Fenotif F1:100%Merah Muda
Genotif F2:100%Mm

C}Fenotif F1:25%:Merah,50%merah muda,25%putih
Genotif F2:25%MM,50%Mm,25%mm

D}Rasio Fenotif F2:1:2:1
Rasio Genotif F2:1:2:1

Anonim mengatakan...

Nama:M.HAIDIR.A
Kelas:IX-3


Jawaban PILIHAN GANDA
1. A
2. D
3. D
4. B
5. C
6. C
7. D
8. D
9. A
10.B
11.C
12.C
13.A
14.A
15.D


JAWABAN ESSAY

P1 ubi cilembu merah )( ubi cilembu putih
MM )( mm
Gamet M )( m
F1 genotip= Mm
Fenotip= merah muda

P2 ubi cilembu merah muda )( ubi cilembu merah muda
Mm )( Mm
Gamet
M m
M MM Mm
m Mm mm
F2 genotip= MM,Mm,Mm,mm
Fenotip= merah, merah muda, merah muda ,putih
Jadi,
A)Gamet p1= M )( m
Gamet p2=Mm )( Mm

b)fenotip f1 =merah muda
genotip f1 =Mm

c) fenotip f2 = merah , merah muda , merah muda , putih
genotip f2= MM , Mm, Mm ,mm

d) rasio fenotipf2=1:2:1
genotipf2=1:2:1

Anonim mengatakan...

Nama:MUAMMAR.A
Kelas:IX-3


Jawaban PILIHAN GANDA
1. A
2. D
3. D
4. B
5. C
6. C
7. D
8. D
9. A
10.B
11.C
12.C
13.A
14.A
15.D


JAWABAN ESSAY

P1 ubi cilembu merah )( ubi cilembu putih
MM )( mm
Gamet M )( m
F1 genotip= Mm
Fenotip= merah muda

P2 ubi cilembu merah muda )( ubi cilembu merah muda
Mm )( Mm
Gamet
M m
M MM Mm
m Mm mm
F2 genotip= MM,Mm,Mm,mm
Fenotip= merah, merah muda, merah muda ,putih
Jadi,
A)Gamet p1= M )( m
Gamet p2=Mm )( Mm

b)fenotip f1 =merah muda
genotip f1 =Mm

c) fenotip f2 = merah , merah muda , merah muda , putih
genotip f2= MM , Mm, Mm ,mm

d) rasio fenotipf2=1:2:1
genotipf2=1:2:1

Anonim mengatakan...

Nama:ANGGA.W
Kelas:IX-3


Jawaban PILIHAN GANDA
1. A
2. D
3. D
4. B
5. C
6. C
7. D
8. D
9. A
10.B
11.C
12.C
13.A
14.A
15.D


JAWABAN ESSAY

P1 ubi cilembu merah )( ubi cilembu putih
MM )( mm
Gamet M )( m
F1 genotip= Mm
Fenotip= merah muda

P2 ubi cilembu merah muda )( ubi cilembu merah muda
Mm )( Mm
Gamet
M m
M MM Mm
m Mm mm
F2 genotip= MM,Mm,Mm,mm
Fenotip= merah, merah muda, merah muda ,putih
Jadi,
A)Gamet p1= M )( m
Gamet p2=Mm )( Mm

b)fenotip f1 =merah muda
genotip f1 =Mm

c) fenotip f2 = merah , merah muda , merah muda , putih
genotip f2= MM , Mm, Mm ,mm

d) rasio fenotipf2=1:2:1
genotipf2=1:2:1

Anonim mengatakan...

Nama:YOSUA.M
Kelas:IX-3


Jawaban PILIHAN GANDA
1. A
2. D
3. D
4. B
5. C
6. C
7. D
8. D
9. A
10.B
11.C
12.C
13.A
14.A
15.D


JAWABAN ESSAY

P1 ubi cilembu merah )( ubi cilembu putih
MM )( mm
Gamet M )( m
F1 genotip= Mm
Fenotip= merah muda

P2 ubi cilembu merah muda )( ubi cilembu merah muda
Mm )( Mm
Gamet
M m
M MM Mm
m Mm mm
F2 genotip= MM,Mm,Mm,mm
Fenotip= merah, merah muda, merah muda ,putih
Jadi,
A)Gamet p1= M )( m
Gamet p2=Mm )( Mm

b)fenotip f1 =merah muda
genotip f1 =Mm

c) fenotip f2 = merah , merah muda , merah muda , putih
genotip f2= MM , Mm, Mm ,mm

d) rasio fenotipf2=1:2:1
genotipf2=1:2:1

Anonim mengatakan...

Nama:DEDE.A.K
Kelas:IX-3


Jawaban PILIHAN GANDA
1. A
2. D
3. D
4. B
5. C
6. C
7. D
8. D
9. A
10.B
11.C
12.C
13.A
14.A
15.D


JAWABAN ESSAY

P1 ubi cilembu merah )( ubi cilembu putih
MM )( mm
Gamet M )( m
F1 genotip= Mm
Fenotip= merah muda

P2 ubi cilembu merah muda )( ubi cilembu merah muda
Mm )( Mm
Gamet
M m
M MM Mm
m Mm mm
F2 genotip= MM,Mm,Mm,mm
Fenotip= merah, merah muda, merah muda ,putih
Jadi,
A)Gamet p1= M )( m
Gamet p2=Mm )( Mm

b)fenotip f1 =merah muda
genotip f1 =Mm

c) fenotip f2 = merah , merah muda , merah muda , putih
genotip f2= MM , Mm, Mm ,mm

d) rasio fenotipf2=1:2:1
genotipf2=1:2:1

Anonim mengatakan...

Nama:PANGESTU.H
Kelas:IX-3


Jawaban PILIHAN GANDA
1. A
2. D
3. D
4. B
5. C
6. C
7. D
8. D
9. A
10.B
11.C
12.C
13.A
14.A
15.D


JAWABAN ESSAY

P1 ubi cilembu merah )( ubi cilembu putih
MM )( mm
Gamet M )( m
F1 genotip= Mm
Fenotip= merah muda

P2 ubi cilembu merah muda )( ubi cilembu merah muda
Mm )( Mm
Gamet
M m
M MM Mm
m Mm mm
F2 genotip= MM,Mm,Mm,mm
Fenotip= merah, merah muda, merah muda ,putih
Jadi,
A)Gamet p1= M )( m
Gamet p2=Mm )( Mm

b)fenotip f1 =merah muda
genotip f1 =Mm

c) fenotip f2 = merah , merah muda , merah muda , putih
genotip f2= MM , Mm, Mm ,mm

d) rasio fenotipf2=1:2:1
genotipf2=1:2:1

Anonim mengatakan...

Nama:JANUAR.E.S
Kelas:IX-3


Jawaban PILIHAN GANDA
1. A
2. D
3. D
4. B
5. C
6. C
7. D
8. D
9. A
10.B
11.C
12.C
13.A
14.A
15.D


JAWABAN ESSAY

P1 ubi cilembu merah )( ubi cilembu putih
MM )( mm
Gamet M )( m
F1 genotip= Mm
Fenotip= merah muda

P2 ubi cilembu merah muda )( ubi cilembu merah muda
Mm )( Mm
Gamet
M m
M MM Mm
m Mm mm
F2 genotip= MM,Mm,Mm,mm
Fenotip= merah, merah muda, merah muda ,putih
Jadi,
A)Gamet p1= M )( m
Gamet p2=Mm )( Mm

b)fenotip f1 =merah muda
genotip f1 =Mm

c) fenotip f2 = merah , merah muda , merah muda , putih
genotip f2= MM , Mm, Mm ,mm

d) rasio fenotipf2=1:2:1
genotipf2=1:2:1

IPA mengatakan...

NAMA;ADI PURWANTO
KELAS;IX-1


1. A
2. B
3. D
4. C
5. B
6. C
7. D
8. B
9. B
10. B

Jawaban essay

F1 = P = Ubi cilembu merah x Ubi cilembu putih
F = merah x putih
G = MM x mm
M x m
M x m






Genotif F2 = P = Ubi cilembu merah muda x Ubi cilembu merah muda
(Mm) x (Mm)
F = pink x pink
G= Mm x Mm

Genotif F2= MM : Mm : mm
1 : 2 : 1 = 25% : 50% : 25%

Fenotif F2= merah ; merah muda ; putih
1 : 2 : 1 = 25% ; 50% ; 25%

Jadi , a) Gamet F1 & F2= Mm x mm : Mm x Mm
b) Fenotif F1 = 100% pink Genotif F1 = 100% Mm
c) Fenotif F2 = merah , pink , putih : Genotif F2= Mm , Mm , mm
d) Rasio fenotif = 1 : 2 : 1 Rasio Genotif = 1 : 2 : 1
25% : 50% : 25% 25% ; 50% : 25%

Anonim mengatakan...

Nama : Reni Saputri
Kelas :IX-1

1. A
2. B
3. D
4. C
5. B
6. C
7. D
8. B
9. B
10. B

Jawaban essay

F1 = P = Ubi cilembu merah x Ubi cilembu putih
F = merah x putih
G = MM x mm
M x m
M x m






Genotif F2 = P = Ubi cilembu merah muda x Ubi cilembu merah muda
(Mm) x (Mm)
F = pink x pink
G= Mm x Mm

Genotif F2= MM : Mm : mm
1 : 2 : 1 = 25% : 50% : 25%

Fenotif F2= merah ; merah muda ; putih
1 : 2 : 1 = 25% ; 50% ; 25%

Jadi , a) Gamet F1 & F2= Mm x mm : Mm x Mm
b) Fenotif F1 = 100% pink Genotif F1 = 100% Mm
c) Fenotif F2 = merah , pink , putih : Genotif F2= Mm , Mm , mm
d) Rasio fenotif = 1 : 2 : 1 Rasio Genotif = 1 : 2 : 1
25% : 50% : 25% 25% ; 50% : 25%

Anonim mengatakan...

Nama : Windi Adityarini
Kelas :IX-1

1. A
2. B
3. D
4. C
5. B
6. C
7. D
8. B
9. B
10. B

Jawaban essay

F1 = P = Ubi cilembu merah x Ubi cilembu putih
F = merah x putih
G = MM x mm
M x m
M x m






Genotif F2 = P = Ubi cilembu merah muda x Ubi cilembu merah muda
(Mm) x (Mm)
F = pink x pink
G= Mm x Mm

Genotif F2= MM : Mm : mm
1 : 2 : 1 = 25% : 50% : 25%

Fenotif F2= merah ; merah muda ; putih
1 : 2 : 1 = 25% ; 50% ; 25%

Jadi , a) Gamet F1 & F2= Mm x mm : Mm x Mm
b) Fenotif F1 = 100% pink Genotif F1 = 100% Mm
c) Fenotif F2 = merah , pink , putih : Genotif F2= Mm , Mm , mm
d) Rasio fenotif = 1 : 2 : 1 Rasio Genotif = 1 : 2 : 1
25% : 50% : 25% 25% ; 50% : 25%

Anonim mengatakan...

Nama : Vivi Dwi Oktavia.A
Kelas :IX-1

1. A
2. B
3. D
4. C
5. B
6. C
7. D
8. B
9. B
10. B

Jawaban essay

F1 = P = Ubi cilembu merah x Ubi cilembu putih
F = merah x putih
G = MM x mm
M x m
M x m






Genotif F2 = P = Ubi cilembu merah muda x Ubi cilembu merah muda
(Mm) x (Mm)
F = pink x pink
G= Mm x Mm

Genotif F2= MM : Mm : mm
1 : 2 : 1 = 25% : 50% : 25%

Fenotif F2= merah ; merah muda ; putih
1 : 2 : 1 = 25% ; 50% ; 25%

Jadi , a) Gamet F1 & F2= Mm x mm : Mm x Mm
b) Fenotif F1 = 100% pink Genotif F1 = 100% Mm
c) Fenotif F2 = merah , pink , putih : Genotif F2= Mm , Mm , mm
d) Rasio fenotif = 1 : 2 : 1 Rasio Genotif = 1 : 2 : 1
25% : 50% : 25% 25% ; 50% : 25%

Anonim mengatakan...

Nama : Erlina Sari
Kelas :IX-1

1. A
2. B
3. D
4. C
5. B
6. C
7. D
8. B
9. B
10. B

Jawaban essay

F1 = P = Ubi cilembu merah x Ubi cilembu putih
F = merah x putih
G = MM x mm
M x m
M x m






Genotif F2 = P = Ubi cilembu merah muda x Ubi cilembu merah muda
(Mm) x (Mm)
F = pink x pink
G= Mm x Mm

Genotif F2= MM : Mm : mm
1 : 2 : 1 = 25% : 50% : 25%

Fenotif F2= merah ; merah muda ; putih
1 : 2 : 1 = 25% ; 50% ; 25%

Jadi , a) Gamet F1 & F2= Mm x mm : Mm x Mm
b) Fenotif F1 = 100% pink Genotif F1 = 100% Mm
c) Fenotif F2 = merah , pink , putih : Genotif F2= Mm , Mm , mm
d) Rasio fenotif = 1 : 2 : 1 Rasio Genotif = 1 : 2 : 1
25% : 50% : 25% 25% ; 50% : 25%

Anonim mengatakan...

Nama : Desi Ratnasari
Kelas :IX-2

1. A
2. B
3. D
4. C
5. B
6. C
7. D
8. B
9. B
10. B

Jawaban essay

F1 = P = Ubi cilembu merah x Ubi cilembu putih
F = merah x putih
G = MM x mm
M x m
M x m






Genotif F2 = P = Ubi cilembu merah muda x Ubi cilembu merah muda
(Mm) x (Mm)
F = pink x pink
G= Mm x Mm

Genotif F2= MM : Mm : mm
1 : 2 : 1 = 25% : 50% : 25%

Fenotif F2= merah ; merah muda ; putih
1 : 2 : 1 = 25% ; 50% ; 25%

Jadi , a) Gamet F1 & F2= Mm x mm : Mm x Mm
b) Fenotif F1 = 100% pink Genotif F1 = 100% Mm
c) Fenotif F2 = merah , pink , putih : Genotif F2= Mm , Mm , mm
d) Rasio fenotif = 1 : 2 : 1 Rasio Genotif = 1 : 2 : 1
25% : 50% : 25% 25% ; 50% : 25%

Anonim mengatakan...

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